20x^2=-22x-6

Solution for 20x^2=-22x-6 equation:

20x^2=-22x-6

We move all terms to the left:

20x^2-(-22x-6)=0

We get rid of parentheses

20x^2+22x+6=0

a = 20; b = 22; c = +6;
Δ = b2-4ac
Δ = 222-4·20·6
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-2}{2*20}=\frac{-24}{40}
=-3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+2}{2*20}=\frac{-20}{40}
=-1/2
$